(n-1)+35=3n

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Solution for (n-1)+35=3n equation: 



(n-1)+35=3n

We move all terms to the left:

(n-1)+35-(3n)=0

We add all the numbers together, and all the variables

-3n+(n-1)+35=0

We get rid of parentheses

-3n+n-1+35=0

We add all the numbers together, and all the variables

-2n+34=0

We move all terms containing n to the left, all other terms to the right

-2n=-34

n=-34/-2

n=+17

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