(n+2)/3+2n-5=5

Solution for (n+2)/3+2n-5=5 equation:

(n+2)/3+2n-5=5

We move all terms to the left:

(n+2)/3+2n-5-(5)=0

We add all the numbers together, and all the variables

2n+(n+2)/3-10=0

We multiply all the terms by the denominator


2n*3+(n+2)-10*3=0

We add all the numbers together, and all the variables

2n*3+(n+2)-30=0

Wy multiply elements

6n+(n+2)-30=0

We get rid of parentheses

6n+n+2-30=0

We add all the numbers together, and all the variables

7n-28=0

We move all terms containing n to the left, all other terms to the right

7n=28

n=28/7

n=4