(n+10)/6=(n-3)/3

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Solution for (n+10)/6=(n-3)/3 equation: 



(n+10)/6=(n-3)/3

We move all terms to the left:

(n+10)/6-((n-3)/3)=0

We calculate fractions


n/()+(-((n-3)*6)/()=0



We calculate terms in parentheses: +(-((n-3)*6)/(), so:

-((n-3)*6)/(

We multiply all the terms by the denominator


-((n-3)*6)



We calculate terms in parentheses: -((n-3)*6), so:

(n-3)*6

We multiply parentheses

6n-18

Back to the equation:

-(6n-18)



We get rid of parentheses

-6n+18

Back to the equation:

+(-6n+18)



We get rid of parentheses

n/()-6n+18=0

We multiply all the terms by the denominator


n-6n*()+18*()=0

We add all the numbers together, and all the variables

n-6n*()=0

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