(m/2)-(1/m)=(6m+5)/(12)

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Solution for (m/2)-(1/m)=(6m+5)/(12) equation: 


D( m )

m = 0

m = 0

m = 0

m in (-oo:0) U (0:+oo)

m/2-(1/m) = (6*m+5)/12 // - (6*m+5)/12

m/2-((6*m+5)/12)-(1/m) = 0

m/2-((6*m+5)/12)-m^-1 = 0

(-1*(6*m+5))/12+m/2-1/m = 0

(-1*2*m*(6*m+5))/(2*12*m)+(12*m^2)/(2*12*m)+(-1*2*12)/(2*12*m) = 0

12*m^2-1*2*m*(6*m+5)-1*2*12 = 0

-10*m-24 = 0

(-10*m-24)/(2*12*m) = 0

(-10*m-24)/(2*12*m) = 0 // * 2*12*m

-10*m-24 = 0

-10*m-24 = 0 // + 24

-10*m = 24 // : -10

m = 24/(-10)

m = -12/5

m = -12/5

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