1/x=16/9x+7

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Solution for 1/x=16/9x+7 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x = (16/9)*x+7 // - (16/9)*x+7

1/x-((16/9)*x)-7 = 0

(-16/9)*x+1/x-7 = 0

1*x^-1-16/9*x^1-7*x^0 = 0

(1*x^0-16/9*x^2-7*x^1)/(x^1) = 0 // * x^2

x^1*(1*x^0-16/9*x^2-7*x^1) = 0

x^1

(-16/9)*x^2-7*x+1 = 0

(-16/9)*x^2-7*x+1 = 0

DELTA = (-7)^2-(1*4*(-16/9))

DELTA = 505/9

DELTA > 0

x = ((505/9)^(1/2)+7)/(2*(-16/9)) or x = (7-(505/9)^(1/2))/(2*(-16/9))

x = -9/32*((505/9)^(1/2)+7) or x = -9/32*(7-(505/9)^(1/2))

x in { -9/32*((505/9)^(1/2)+7), -9/32*(7-(505/9)^(1/2))}

x in { -9/32*((505/9)^(1/2)+7), -9/32*(7-(505/9)^(1/2)) }

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