(m-5)/2=(2m+5)/7

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Solution for (m-5)/2=(2m+5)/7 equation: 



(m-5)/2=(2m+5)/7

We move all terms to the left:

(m-5)/2-((2m+5)/7)=0

We calculate fractions


m/()+(-((2m+5)*2)/()=0



We calculate terms in parentheses: +(-((2m+5)*2)/(), so:

-((2m+5)*2)/(

We multiply all the terms by the denominator


-((2m+5)*2)



We calculate terms in parentheses: -((2m+5)*2), so:

(2m+5)*2

We multiply parentheses

4m+10

Back to the equation:

-(4m+10)



We get rid of parentheses

-4m-10

Back to the equation:

+(-4m-10)



We get rid of parentheses

m/()-4m-10=0

We multiply all the terms by the denominator


m-4m*()-10*()=0

We add all the numbers together, and all the variables

m-4m*()=0

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