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(5a-7)/(3a+1)=4/5
We move all terms to the left:
(5a-7)/(3a+1)-(4/5)=0
Domain of the equation: (3a+1)!=0We add all the numbers together, and all the variables
We move all terms containing a to the left, all other terms to the right
3a!=-1
a!=-1/3
a!=-1/3
a∈R
(5a-7)/(3a+1)-(+4/5)=0
We get rid of parentheses
(5a-7)/(3a+1)-4/5=0
We calculate fractions
(25a-35)/(15a+5)+(-12a-4)/(15a+5)=0
We multiply all the terms by the denominator
(25a-35)+(-12a-4)=0
We get rid of parentheses
25a-12a-35-4=0
We add all the numbers together, and all the variables
13a-39=0
We move all terms containing a to the left, all other terms to the right
13a=39
a=39/13
a=3
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