(m-1)(2m+5)=(m+1)(2m)

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Solution for (m-1)(2m+5)=(m+1)(2m) equation: 



(m-1)(2m+5)=(m+1)(2m)

We move all terms to the left:

(m-1)(2m+5)-((m+1)(2m))=0

We multiply parentheses ..

(+2m^2+5m-2m-5)-((m+1)2m)=0



We calculate terms in parentheses: -((m+1)2m), so:

(m+1)2m

We multiply parentheses

2m^2+2m

Back to the equation:

-(2m^2+2m)



We get rid of parentheses

2m^2-2m^2+5m-2m-2m-5=0

We add all the numbers together, and all the variables

m-5=0

We move all terms containing m to the left, all other terms to the right

m=5

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