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(k=3)-(3k-5)=
We move all terms to the left:
(k-(3)-(3k-5))=0
We calculate terms in parentheses: +(k-3-(3k-5)), so:We get rid of parentheses
k-3-(3k-5)
determiningTheFunctionDomain k-(3k-5)-3
We get rid of parentheses
k-3k+5-3
We add all the numbers together, and all the variables
-2k+2
Back to the equation:
+(-2k+2)
-2k+2=0
We move all terms containing k to the left, all other terms to the right
-2k=-2
k=-2/-2
k=1
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