(k+22)(4k+9)=0

Solution for (k+22)(4k+9)=0 equation:

(k+22)(4k+9)=0

We multiply parentheses ..

(+4k^2+9k+88k+198)=0

We get rid of parentheses

4k^2+9k+88k+198=0

We add all the numbers together, and all the variables

4k^2+97k+198=0

a = 4; b = 97; c = +198;
Δ = b2-4ac
Δ = 972-4·4·198
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(97)-79}{2*4}=\frac{-176}{8}
=-22
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(97)+79}{2*4}=\frac{-18}{8}
=-2+1/4
$