(2p+9)(p-17)=0

Solution for (2p+9)(p-17)=0 equation:

(2p+9)(p-17)=0

We multiply parentheses ..

(+2p^2-34p+9p-153)=0

We get rid of parentheses

2p^2-34p+9p-153=0

We add all the numbers together, and all the variables

2p^2-25p-153=0

a = 2; b = -25; c = -153;
Δ = b2-4ac
Δ = -252-4·2·(-153)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-43}{2*2}=\frac{-18}{4}
=-4+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+43}{2*2}=\frac{68}{4}
=17
$