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(k+1)(12-1/(k+1))-k(12-1/k)=1
We move all terms to the left:
(k+1)(12-1/(k+1))-k(12-1/k)-(1)=0
Domain of the equation: (k+1))!=0
k∈R
Domain of the equation: k)!=0We add all the numbers together, and all the variables
k!=0/1
k!=0
k∈R
(k+1)(12-1/(k+1))-k(-1/k+12)-1=0
We multiply parentheses
1k^2+(k+1)(12-1/(k+1))-12k-1=0
We multiply all the terms by the denominator
1k^2*(k+1))+(k-12k*(k+1))-1*(k-1+1)(12+1))=0
We add all the numbers together, and all the variables
1k^2*(k+1))+(k-12k*(k+1))-1*(+k)13)=0
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