(k+1)(12-(1/(k+1)))-k(12-(1/k))=1

Solution for (k+1)(12-(1/(k+1)))-k(12-(1/k))=1 equation:

(k+1)(12-(1/(k+1)))-k(12-(1/k))=1

We move all terms to the left:

(k+1)(12-(1/(k+1)))-k(12-(1/k))-(1)=0


Domain of the equation: (k+1)))!=0

k∈R



Domain of the equation: k))!=0

k!=0/1

k!=0

k∈R


We add all the numbers together, and all the variables

(k+1)(12-(1/(k+1)))-k(12-(+1/k))-1=0

We calculate fractions


()/(k+1)))*k))+(-k(12-(+1*(k+1))))/(k+1)))*k))-1=0

We calculate fractions


(()*(k+1)))*k))-1)/((k+1)))*k))+(-k(12-(+1*(k*(k+1)))*k))-1)+1)))*(k+1)))*k))+(-k(12-(+1*k/((k+1)))*k))+(-k(12-(+1*(k*(k+1)))*k))-1)=0


We calculate terms in parentheses: +(()*(k+1)))*k))-1)/((k+1)))*k))+(-k(12-(+1*(k*(k+1)))*k))-1)+1)))*(k+1)))*k))+(-k(12-(+1*k/((k+1)))*k))+(-k(12-(+1*(k*(k+1)))*k))-1), so:

()*(k+1)))*k))-1)/((k+1)))*k))+(-k(12-(+1*(k*(k+1)))*k))-1)+1)))*(k+1)))*k))+(-k(12-(+1*k/((k+1)))*k))+(-k(12-(+1*(k*(k+1)))*k))-1

We can not solve this equation