(h+14)+(h-14)+14=(h+10)+14+150

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Solution for (h+14)+(h-14)+14=(h+10)+14+150 equation:



(h+14)+(h-14)+14=(h+10)+14+150
We move all terms to the left:
(h+14)+(h-14)+14-((h+10)+14+150)=0
We get rid of parentheses
h+h-((h+10)+14+150)+14-14+14=0
We calculate terms in parentheses: -((h+10)+14+150), so:
(h+10)+14+150
We add all the numbers together, and all the variables
(h+10)+164
We get rid of parentheses
h+10+164
We add all the numbers together, and all the variables
h+174
Back to the equation:
-(h+174)
We add all the numbers together, and all the variables
2h-(h+174)+14=0
We get rid of parentheses
2h-h-174+14=0
We add all the numbers together, and all the variables
h-160=0
We move all terms containing h to the left, all other terms to the right
h=160

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