(h+12)+(h-12)+12=(h+12)+12+180

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Solution for (h+12)+(h-12)+12=(h+12)+12+180 equation: 



(h+12)+(h-12)+12=(h+12)+12+180

We move all terms to the left:

(h+12)+(h-12)+12-((h+12)+12+180)=0

We get rid of parentheses

h+h-((h+12)+12+180)+12-12+12=0



We calculate terms in parentheses: -((h+12)+12+180), so:

(h+12)+12+180

We add all the numbers together, and all the variables

(h+12)+192

We get rid of parentheses

h+12+192

We add all the numbers together, and all the variables

h+204

Back to the equation:

-(h+204)



We add all the numbers together, and all the variables

2h-(h+204)+12=0

We get rid of parentheses

2h-h-204+12=0

We add all the numbers together, and all the variables

h-192=0

We move all terms containing h to the left, all other terms to the right

h=192

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