(h+1)(2h-1)=

Solution for (h+1)(2h-1)= equation:

Simplifying
(h + 1)(2h + -1) = 0

Reorder the terms:
(1 + h)(2h + -1) = 0

Reorder the terms:
(1 + h)(-1 + 2h) = 0

Multiply (1 + h) * (-1 + 2h)
(1(-1 + 2h) + h(-1 + 2h)) = 0
((-1 * 1 + 2h * 1) + h(-1 + 2h)) = 0
((-1 + 2h) + h(-1 + 2h)) = 0
(-1 + 2h + (-1 * h + 2h * h)) = 0
(-1 + 2h + (-1h + 2h2)) = 0

Combine like terms: 2h + -1h = 1h
(-1 + 1h + 2h2) = 0

Solving
-1 + 1h + 2h2 = 0

Solving for variable 'h'.

Factor a trinomial.
(-1 + -1h)(1 + -2h) = 0

Subproblem 1
Set the factor '(-1 + -1h)' equal to zero and attempt to solve:

Simplifying
-1 + -1h = 0

Solving
-1 + -1h = 0

Move all terms containing h to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1h = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1h = 0 + 1
-1h = 0 + 1

Combine like terms: 0 + 1 = 1
-1h = 1

Divide each side by '-1'.
h = -1

Simplifying
h = -1
Subproblem 2
Set the factor '(1 + -2h)' equal to zero and attempt to solve:

Simplifying
1 + -2h = 0

Solving
1 + -2h = 0

Move all terms containing h to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -2h = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2h = 0 + -1
-2h = 0 + -1

Combine like terms: 0 + -1 = -1
-2h = -1

Divide each side by '-2'.
h = 0.5

Simplifying
h = 0.5
Solution
h = {-1, 0.5}