(g-1)(6g+9)=0

Solution for (g-1)(6g+9)=0 equation:

(g-1)(6g+9)=0

We multiply parentheses ..

(+6g^2+9g-6g-9)=0

We get rid of parentheses

6g^2+9g-6g-9=0

We add all the numbers together, and all the variables

6g^2+3g-9=0

a = 6; b = 3; c = -9;
Δ = b2-4ac
Δ = 32-4·6·(-9)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-15}{2*6}=\frac{-18}{12}
=-1+1/2
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+15}{2*6}=\frac{12}{12}
=1
$