10x-2(x-3)=x+27

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Solution for 10x-2(x-3)=x+27 equation: 



10x-2(x-3)=x+27

We move all terms to the left:

10x-2(x-3)-(x+27)=0

We multiply parentheses

10x-2x-(x+27)+6=0

We get rid of parentheses

10x-2x-x-27+6=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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