(c=4)+(3c+9)=

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Solution for (c=4)+(3c+9)= equation: 



(c=4)+(3c+9)=

We move all terms to the left:

(c-(4)+(3c+9))=0



We calculate terms in parentheses: +(c-4+(3c+9)), so:

c-4+(3c+9)

determiningTheFunctionDomain
c+(3c+9)-4

We get rid of parentheses

c+3c+9-4

We add all the numbers together, and all the variables

4c+5

Back to the equation:

+(4c+5)



We get rid of parentheses

4c+5=0

We move all terms containing c to the left, all other terms to the right

4c=-5

c=-5/4

c=-1+1/4

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