4(a-8)+14=10(a+2)-6a-38

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Solution for 4(a-8)+14=10(a+2)-6a-38 equation: 



4(a-8)+14=10(a+2)-6a-38

We move all terms to the left:

4(a-8)+14-(10(a+2)-6a-38)=0

We multiply parentheses

4a-(10(a+2)-6a-38)-32+14=0



We calculate terms in parentheses: -(10(a+2)-6a-38), so:

10(a+2)-6a-38

We add all the numbers together, and all the variables

-6a+10(a+2)-38

We multiply parentheses

-6a+10a+20-38

We add all the numbers together, and all the variables

4a-18

Back to the equation:

-(4a-18)



We add all the numbers together, and all the variables

4a-(4a-18)-18=0

We get rid of parentheses

4a-4a+18-18=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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