(c+7)(c-12)=0

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Solution for (c+7)(c-12)=0 equation:


Simplifying
(c + 7)(c + -12) = 0

Reorder the terms:
(7 + c)(c + -12) = 0

Reorder the terms:
(7 + c)(-12 + c) = 0

Multiply (7 + c) * (-12 + c)
(7(-12 + c) + c(-12 + c)) = 0
((-12 * 7 + c * 7) + c(-12 + c)) = 0
((-84 + 7c) + c(-12 + c)) = 0
(-84 + 7c + (-12 * c + c * c)) = 0
(-84 + 7c + (-12c + c2)) = 0

Combine like terms: 7c + -12c = -5c
(-84 + -5c + c2) = 0

Solving
-84 + -5c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-7 + -1c)(12 + -1c) = 0

Subproblem 1

Set the factor '(-7 + -1c)' equal to zero and attempt to solve: Simplifying -7 + -1c = 0 Solving -7 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -1c = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -1c = 0 + 7 -1c = 0 + 7 Combine like terms: 0 + 7 = 7 -1c = 7 Divide each side by '-1'. c = -7 Simplifying c = -7

Subproblem 2

Set the factor '(12 + -1c)' equal to zero and attempt to solve: Simplifying 12 + -1c = 0 Solving 12 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1c = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1c = 0 + -12 -1c = 0 + -12 Combine like terms: 0 + -12 = -12 -1c = -12 Divide each side by '-1'. c = 12 Simplifying c = 12

Solution

c = {-7, 12}

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