12/b=b/27

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Solution for 12/b=b/27 equation: 


D( b )

b = 0

b = 0

b = 0

b in (-oo:0) U (0:+oo)

12/b = b/27 // - b/27

12/b-(b/27) = 0

12*b^-1-1/27*b^1 = 0

(12*b^0-1/27*b^2)/(b^1) = 0 // * b^2

b^1*(12*b^0-1/27*b^2) = 0

b^1

(-1/27)*b^2+12 = 0

(-1/27)*b^2+12 = 0

DELTA = 0^2-(4*12*(-1/27))

DELTA = 16/9

DELTA > 0

b = ((16/9)^(1/2)+0)/(2*(-1/27)) or b = (0-(16/9)^(1/2))/(2*(-1/27))

b = -18 or b = 18

b in { -18, 18} 

b in { -18, 18 }

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