(b+2)(b-3)=50

Solution for (b+2)(b-3)=50 equation:

(b+2)(b-3)=50

We move all terms to the left:

(b+2)(b-3)-(50)=0

We multiply parentheses ..

(+b^2-3b+2b-6)-50=0

We get rid of parentheses

b^2-3b+2b-6-50=0

We add all the numbers together, and all the variables

b^2-1b-56=0

a = 1; b = -1; c = -56;
Δ = b2-4ac
Δ = -12-4·1·(-56)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-15}{2*1}=\frac{-14}{2}
=-7
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+15}{2*1}=\frac{16}{2}
=8
$