(a+6)(a-2)=2+a-10

Solution for (a+6)(a-2)=2+a-10 equation:

(a+6)(a-2)=2+a-10

We move all terms to the left:

(a+6)(a-2)-(2+a-10)=0

We add all the numbers together, and all the variables

(a+6)(a-2)-(a-8)=0

We get rid of parentheses

(a+6)(a-2)-a+8=0

We multiply parentheses ..

(+a^2-2a+6a-12)-a+8=0

We add all the numbers together, and all the variables

(+a^2-2a+6a-12)-1a+8=0

We get rid of parentheses

a^2-2a+6a-1a-12+8=0

We add all the numbers together, and all the variables

a^2+3a-4=0

a = 1; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·1·(-4)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-5}{2*1}=\frac{-8}{2}
=-4
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+5}{2*1}=\frac{2}{2}
=1
$