(a+4b)/4=(2a+b)/3

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Solution for (a+4b)/4=(2a+b)/3 equation: 


x in (-oo:+oo)

(a+4*b)/4 = (2*a+b)/3 // - (2*a+b)/3

(a+4*b)/4-((2*a+b)/3) = 0

(a+4*b)/4+(-1*(2*a+b))/3 = 0

(3*(a+4*b))/(3*4)+(-1*4*(2*a+b))/(3*4) = 0

3*(a+4*b)-1*4*(2*a+b) = 0

8*b-5*a = 0

(8*b-5*a)/(3*4) = 0

(8*b-5*a)/(3*4) = 0 // * 3*4

8*b-5*a = 0

x belongs to the empty set

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