1/(2n-3)=2/(3n-1)

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Solution for 1/(2n-3)=2/(3n-1) equation:


D( n )

3*n-1 = 0

2*n-3 = 0

3*n-1 = 0

3*n-1 = 0

3*n-1 = 0 // + 1

3*n = 1 // : 3

n = 1/3

2*n-3 = 0

2*n-3 = 0

2*n-3 = 0 // + 3

2*n = 3 // : 2

n = 3/2

n in (-oo:1/3) U (1/3:3/2) U (3/2:+oo)

1/(2*n-3) = 2/(3*n-1) // - 2/(3*n-1)

1/(2*n-3)-(2/(3*n-1)) = 0

1/(2*n-3)-2*(3*n-1)^-1 = 0

1/(2*n-3)-2/(3*n-1) = 0

(1*(3*n-1))/((2*n-3)*(3*n-1))+(-2*(2*n-3))/((2*n-3)*(3*n-1)) = 0

1*(3*n-1)-2*(2*n-3) = 0

5-n = 0

(5-n)/((2*n-3)*(3*n-1)) = 0

(5-n)/((2*n-3)*(3*n-1)) = 0 // * (2*n-3)*(3*n-1)

5-n = 0

5-n = 0 // - 5

-n = -5 // * -1

n = 5

n = 5

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