(a+2)/5=-2+a

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Solution for (a+2)/5=-2+a equation: 


a in (-oo:+oo)

(a+2)/5 = a-2 // - a-2

(a+2)/5-a+2 = 0

(a+2)/5+(5*(-a))/5+(2*5)/5 = 0

a+5*(-a)+2*5+2 = 0

2-4*a+10 = 0

12-4*a = 0

(12-4*a)/5 = 0

(12-4*a)/5 = 0 // * 5

12-4*a = 0

12-4*a = 0 // - 12

-4*a = -12 // : -4

a = -12/(-4)

a = 3

a = 3

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