(3a+1)(a-2)/(a-2)(a-3)-(3a+1)(a+2)/2(a-3)

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Solution for (3a+1)(a-2)/(a-2)(a-3)-(3a+1)(a+2)/2(a-3) equation:


D( a )

a-2 = 0

a-2 = 0

a-2 = 0

a-2 = 0 // + 2

a = 2

a in (-oo:2) U (2:+oo)

(((3*a+1)*(a-2))/(a-2))*(a-3)-((((3*a+1)*(a+2))/2)*(a-3)) = 0

(3*a+1)*(a-3)+(-1*(3*a+1)*(a+2)*(a-3))/2 = 0

(2*(3*a+1)*(a-3))/2+(-1*(3*a+1)*(a+2)*(a-3))/2 = 0

2*(3*a+1)*(a-3)-1*(3*a+1)*(a+2)*(a-3) = 0

8*a^2-3*a^3+3*a = 0

8*a^2-3*a^3+3*a = 0

a*(8*a-3*a^2+3) = 0

8*a-3*a^2+3 = 0

DELTA = 8^2-(-3*3*4)

DELTA = 100

DELTA > 0

a = (100^(1/2)-8)/(-3*2) or a = (-100^(1/2)-8)/(-3*2)

a = -1/3 or a = 3

a*(a+1/3)*(a-3) = 0

(a*(a+1/3)*(a-3))/2 = 0

(a*(a+1/3)*(a-3))/2 = 0 // * 2

a*(a+1/3)*(a-3) = 0

( a+1/3 )

a+1/3 = 0 // - 1/3

a = -1/3

( a-3 )

a-3 = 0 // + 3

a = 3

( a )

a = 0

a in { -1/3, 3, 0 }

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