(a*a)+(a*a)=a+a

Solution for (a*a)+(a*a)=a+a equation:

(a*a)+(a*a)=a+a

We move all terms to the left:

(a*a)+(a*a)-(a+a)=0

We add all the numbers together, and all the variables

(+a*a)+(+a*a)-(+2a)=0

We get rid of parentheses

a*a+a*a-2a=0

We add all the numbers together, and all the variables

-2a+a*a+a*a=0

Wy multiply elements

a^2+a^2-2a=0

We add all the numbers together, and all the variables

2a^2-2a=0

a = 2; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·2·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*2}=\frac{0}{4}
=0
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*2}=\frac{4}{4}
=1
$