4q+6-2(2+3q)=3(4q+10)

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Solution for 4q+6-2(2+3q)=3(4q+10) equation: 



4q+6-2(2+3q)=3(4q+10)

We move all terms to the left:

4q+6-2(2+3q)-(3(4q+10))=0

We add all the numbers together, and all the variables

4q-2(3q+2)-(3(4q+10))+6=0

We multiply parentheses

4q-6q-(3(4q+10))-4+6=0



We calculate terms in parentheses: -(3(4q+10)), so:

3(4q+10)

We multiply parentheses

12q+30

Back to the equation:

-(12q+30)



We add all the numbers together, and all the variables

-2q-(12q+30)+2=0

We get rid of parentheses

-2q-12q-30+2=0

We add all the numbers together, and all the variables

-14q-28=0

We move all terms containing q to the left, all other terms to the right

-14q=28

q=28/-14

q=-2

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