(Y+3)(y-5)=2y+2

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Solution for (Y+3)(y-5)=2y+2 equation: 



(+3)(Y-5)=2Y+2

We move all terms to the left:

(+3)(Y-5)-(2Y+2)=0

We add all the numbers together, and all the variables

3(Y-5)-(2Y+2)=0

We multiply parentheses

3Y-(2Y+2)-15=0

We get rid of parentheses

3Y-2Y-2-15=0

We add all the numbers together, and all the variables

Y-17=0

We move all terms containing Y to the left, all other terms to the right

Y=17

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