(X2+3x+1)(X2+3x-3)=5

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Solution for (X2+3x+1)(X2+3x-3)=5 equation: 



(X2+3X+1)(X2+3X-3)=5

We move all terms to the left:

(X2+3X+1)(X2+3X-3)-(5)=0

We add all the numbers together, and all the variables

(+X^2+3X+1)(+X^2+3X-3)-5=0

We move all terms containing X to the left, all other terms to the right

(+X^2+3X+1)(+X^2+3X-3)=5

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