3(t-4)=4(5t+1)

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Solution for 3(t-4)=4(5t+1) equation: 



3(t-4)=4(5t+1)

We move all terms to the left:

3(t-4)-(4(5t+1))=0

We multiply parentheses

3t-(4(5t+1))-12=0



We calculate terms in parentheses: -(4(5t+1)), so:

4(5t+1)

We multiply parentheses

20t+4

Back to the equation:

-(20t+4)



We get rid of parentheses

3t-20t-4-12=0

We add all the numbers together, and all the variables

-17t-16=0

We move all terms containing t to the left, all other terms to the right

-17t=16

t=16/-17

t=-16/17

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