(X2+10x)/2=12

Solution for (X2+10x)/2=12 equation:

(X2+10X)/2=12

We move all terms to the left:

(X2+10X)/2-(12)=0

We add all the numbers together, and all the variables

(+X^2+10X)/2-12=0

We multiply all the terms by the denominator


(+X^2+10X)-12*2=0

We add all the numbers together, and all the variables

(+X^2+10X)-24=0

We get rid of parentheses

X^2+10X-24=0

a = 1; b = 10; c = -24;
Δ = b2-4ac
Δ = 102-4·1·(-24)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-14}{2*1}=\frac{-24}{2}
=-12
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+14}{2*1}=\frac{4}{2}
=2
$