(X-8)(x+14)-(x+3)(x+2)+1=0

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Solution for (X-8)(x+14)-(x+3)(x+2)+1=0 equation: 



(X-8)(X+14)-(X+3)(X+2)+1=0

We multiply parentheses ..

(+X^2+14X-8X-112)-(X+3)(X+2)+1=0

We get rid of parentheses

X^2+14X-8X-(X+3)(X+2)-112+1=0

We multiply parentheses ..

X^2-(+X^2+2X+3X+6)+14X-8X-112+1=0

We add all the numbers together, and all the variables

X^2-(+X^2+2X+3X+6)+6X-111=0

We get rid of parentheses

X^2-X^2-2X-3X+6X-6-111=0

We add all the numbers together, and all the variables

X-117=0

We move all terms containing X to the left, all other terms to the right

X=117

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