(X-4)+(x+1)+(x-2)+(x+3)+x=33

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Solution for (X-4)+(x+1)+(x-2)+(x+3)+x=33 equation: 



(X-4)+(X+1)+(X-2)+(X+3)+X=33

We move all terms to the left:

(X-4)+(X+1)+(X-2)+(X+3)+X-(33)=0

We add all the numbers together, and all the variables

X+(X-4)+(X+1)+(X-2)+(X+3)-33=0

We get rid of parentheses

X+X+X+X+X-4+1-2+3-33=0

We add all the numbers together, and all the variables

5X-35=0

We move all terms containing X to the left, all other terms to the right

5X=35

X=35/5

X=7

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