(X-4)(x-2)=14

Solution for (X-4)(x-2)=14 equation:

(X-4)(X-2)=14

We move all terms to the left:

(X-4)(X-2)-(14)=0

We multiply parentheses ..

(+X^2-2X-4X+8)-14=0

We get rid of parentheses

X^2-2X-4X+8-14=0

We add all the numbers together, and all the variables

X^2-6X-6=0

a = 1; b = -6; c = -6;
Δ = b2-4ac
Δ = -62-4·1·(-6)
Δ = 60
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60}=\sqrt{4*15}=\sqrt{4}*\sqrt{15}=2\sqrt{15}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{15}}{2*1}=\frac{6-2\sqrt{15}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{15}}{2*1}=\frac{6+2\sqrt{15}}{2}
$