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(X-4)(2X+5)+(3-4X)(X-4)=0
We add all the numbers together, and all the variables
(X-4)(2X+5)+(-4X+3)(X-4)=0
We multiply parentheses ..
(+2X^2+5X-8X-20)+(-4X+3)(X-4)=0
We get rid of parentheses
2X^2+5X-8X+(-4X+3)(X-4)-20=0
We multiply parentheses ..
2X^2+(-4X^2+16X+3X-12)+5X-8X-20=0
We add all the numbers together, and all the variables
2X^2+(-4X^2+16X+3X-12)-3X-20=0
We get rid of parentheses
2X^2-4X^2+16X+3X-3X-12-20=0
We add all the numbers together, and all the variables
-2X^2+16X-32=0
a = -2; b = 16; c = -32;
Δ = b2-4ac
Δ = 162-4·(-2)·(-32)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$X=\frac{-b}{2a}=\frac{-16}{-4}=+4$
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