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((6x+3)/7)+((9x+1)/2)=17
We move all terms to the left:
((6x+3)/7)+((9x+1)/2)-(17)=0
We calculate fractions
(12x+6)/()+(63x+7)/()-17=0
We multiply all the terms by the denominator
(12x+6)+(63x+7)-17*()=0
We add all the numbers together, and all the variables
(12x+6)+(63x+7)=0
We get rid of parentheses
12x+63x+6+7=0
We add all the numbers together, and all the variables
75x+13=0
We move all terms containing x to the left, all other terms to the right
75x=-13
x=-13/75
x=-13/75
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