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(X-3)(5X-7)=0
We multiply parentheses ..
(+5X^2-7X-15X+21)=0
We get rid of parentheses
5X^2-7X-15X+21=0
We add all the numbers together, and all the variables
5X^2-22X+21=0
a = 5; b = -22; c = +21;
Δ = b2-4ac
Δ = -222-4·5·21
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-8}{2*5}=\frac{14}{10} =1+2/5 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+8}{2*5}=\frac{30}{10} =3 $
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