7+(2/5y)=(3/5)y-4

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Solution for 7+(2/5y)=(3/5)y-4 equation: 



7+(2/5y)=(3/5)y-4

We move all terms to the left:

7+(2/5y)-((3/5)y-4)=0



Domain of the equation: 5y)!=0

y!=0/1

y!=0

y∈R





Domain of the equation: 5)y-4)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+2/5y)-((+3/5)y-4)+7=0

We get rid of parentheses

2/5y-((+3/5)y-4)+7=0

We calculate fractions


10y/25y^2+(-((+3*5y)/25y^2+7=0

We calculate fractions

We do not support eypression: y^4

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