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(X-13)-(X-5)2X=0
We multiply parentheses
-2X^2+(X-13)+10X=0
We get rid of parentheses
-2X^2+X+10X-13=0
We add all the numbers together, and all the variables
-2X^2+11X-13=0
a = -2; b = 11; c = -13;
Δ = b2-4ac
Δ = 112-4·(-2)·(-13)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{17}}{2*-2}=\frac{-11-\sqrt{17}}{-4} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{17}}{2*-2}=\frac{-11+\sqrt{17}}{-4} $
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