(X-1)/5=(2x-2)/15

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Solution for (X-1)/5=(2x-2)/15 equation: 



(X-1)/5=(2X-2)/15

We move all terms to the left:

(X-1)/5-((2X-2)/15)=0

We calculate fractions


X/()+(-((2X-2)*5)/()=0



We calculate terms in parentheses: +(-((2X-2)*5)/(), so:

-((2X-2)*5)/(

We multiply all the terms by the denominator


-((2X-2)*5)



We calculate terms in parentheses: -((2X-2)*5), so:

(2X-2)*5

We multiply parentheses

10X-10

Back to the equation:

-(10X-10)



We get rid of parentheses

-10X+10

Back to the equation:

+(-10X+10)



We get rid of parentheses

X/()-10X+10=0

We multiply all the terms by the denominator


X-10X*()+10*()=0

We add all the numbers together, and all the variables

X-10X*()=0

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