(X-1)(x-5)=(x-1)(x-2)+(x+4)

Solution for (X-1)(x-5)=(x-1)(x-2)+(x+4) equation:

(X-1)(X-5)=(X-1)(X-2)+(X+4)

We move all terms to the left:

(X-1)(X-5)-((X-1)(X-2)+(X+4))=0

We multiply parentheses ..

(+X^2-5X-1X+5)-((X-1)(X-2)+(X+4))=0


We calculate terms in parentheses: -((X-1)(X-2)+(X+4)), so:

(X-1)(X-2)+(X+4)

We get rid of parentheses

(X-1)(X-2)+X+4

We multiply parentheses ..

(+X^2-2X-1X+2)+X+4

We get rid of parentheses

X^2-2X-1X+X+2+4

We add all the numbers together, and all the variables

X^2-2X+6

Back to the equation:

-(X^2-2X+6)


We get rid of parentheses

X^2-X^2-5X-1X+2X+5-6=0

We add all the numbers together, and all the variables

-4X-1=0

We move all terms containing X to the left, all other terms to the right

-4X=1

X=1/-4

X=-1/4