4/5+3(a)=1/5-(4a)

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Solution for 4/5+3(a)=1/5-(4a) equation: 



4/5+3(a)=1/5-(4a)

We move all terms to the left:

4/5+3(a)-(1/5-(4a))=0



Domain of the equation: 5-4a)!=0

We move all terms containing a to the left, all other terms to the right

-4a)!=-5

a!=-5/1

a!=-5

a∈R



We add all the numbers together, and all the variables

3a-(-4a+1/5)+4/5=0

We get rid of parentheses

3a+4a-1/5+4/5=0

We multiply all the terms by the denominator


3a*5+4a*5-1+4=0

We add all the numbers together, and all the variables

3a*5+4a*5+3=0

Wy multiply elements

15a+20a+3=0

We add all the numbers together, and all the variables

35a+3=0

We move all terms containing a to the left, all other terms to the right

35a=-3

a=-3/35

a=-3/35

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