(X-1)(x-2)(x+4)(x+5)=112

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Solution for (X-1)(x-2)(x+4)(x+5)=112 equation: 



(X-1)(X-2)(X+4)(X+5)=112

We move all terms to the left:

(X-1)(X-2)(X+4)(X+5)-(112)=0

We multiply parentheses ..

(+X^2-2X-1X+2)(X+4)(X+5)-112=0

We multiply parentheses ..

(+X^2-2X-1X+2)(+X^2+5X+4X+20)-112=0

We move all terms containing X to the left, all other terms to the right

(+X^2-2X-1X+2)(+X^2+5X+4X+20)=112

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