(x+12)+(3x-2)+(4x-16)=180

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Solution for (x+12)+(3x-2)+(4x-16)=180 equation: 



(x+12)+(3x-2)+(4x-16)=180

We move all terms to the left:

(x+12)+(3x-2)+(4x-16)-(180)=0

We get rid of parentheses

x+3x+4x+12-2-16-180=0

We add all the numbers together, and all the variables

8x-186=0

We move all terms containing x to the left, all other terms to the right

8x=186

x=186/8

x=23+1/4

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