(X-1)(x+2)=(x+2)(x-3)

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Solution for (X-1)(x+2)=(x+2)(x-3) equation: 



(X-1)(X+2)=(X+2)(X-3)

We move all terms to the left:

(X-1)(X+2)-((X+2)(X-3))=0

We multiply parentheses ..

(+X^2+2X-1X-2)-((X+2)(X-3))=0



We calculate terms in parentheses: -((X+2)(X-3)), so:

(X+2)(X-3)

We multiply parentheses ..

(+X^2-3X+2X-6)

We get rid of parentheses

X^2-3X+2X-6

We add all the numbers together, and all the variables

X^2-1X-6

Back to the equation:

-(X^2-1X-6)



We get rid of parentheses

X^2-X^2+2X-1X+1X-2+6=0

We add all the numbers together, and all the variables

2X+4=0

We move all terms containing X to the left, all other terms to the right

2X=-4

X=-4/2

X=-2

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