8z+4(4z+3)=4(6z+4)-4

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Solution for 8z+4(4z+3)=4(6z+4)-4 equation: 



8z+4(4z+3)=4(6z+4)-4

We move all terms to the left:

8z+4(4z+3)-(4(6z+4)-4)=0

We multiply parentheses

8z+16z-(4(6z+4)-4)+12=0



We calculate terms in parentheses: -(4(6z+4)-4), so:

4(6z+4)-4

We multiply parentheses

24z+16-4

We add all the numbers together, and all the variables

24z+12

Back to the equation:

-(24z+12)



We add all the numbers together, and all the variables

24z-(24z+12)+12=0

We get rid of parentheses

24z-24z-12+12=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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