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(X+9)(3X+5)=0
We multiply parentheses ..
(+3X^2+5X+27X+45)=0
We get rid of parentheses
3X^2+5X+27X+45=0
We add all the numbers together, and all the variables
3X^2+32X+45=0
a = 3; b = 32; c = +45;
Δ = b2-4ac
Δ = 322-4·3·45
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-22}{2*3}=\frac{-54}{6} =-9 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+22}{2*3}=\frac{-10}{6} =-1+2/3 $
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